The circle: angles, chords and tangents
Central and inscribed angles, the tangent–radius right angle, chord and tangent length relations, arc length and sector area.
First, the rules
Angles, chords and tangents
Three families of facts: angles standing on an arc, lengths of crossing chords and tangents, and the arc and sector formulas. Each comes with a picture — draw the radii and the facts fall out.
All inscribed angles on the same arc are equal.
two tangents from one point are equal: |PA| = |PB|
In radians: arc = rθ, sector = ½ r²θ.
See it
Inscribed angle vs central angle
Drag the three points. However P moves along its arc, angle APB stays half of angle AOB.
Step by step
Worked examples
Angles on a circle
inscribed · semicircleA, B, C, D lie on a circle with centre O. Angle AOB = 110°, and AC is a diameter. Find (a) the inscribed angle ADB on the major arc, (b) angle ABC.
Ask yourself: Inscribed angle = half the central angle on the same arc. A diameter gives a right angle.
Show the solution
- (a) D sees arc AB with central angle 110°: ∠ADB = 110° / 2 = 55°.
- (b) B stands on the diameter AC, so ∠ABC = 90°.
- Check: the reflex angle AOB is 250°, so an inscribed angle on the minor arc (the other side) would be 125°; 55° + 125° = 180°, as a cyclic quadrilateral demands.
Answer (a) 55° (b) 90°
Chords and a tangent
lengths(a) Chords AB and CD cross at P with |PA| = 4, |PB| = 9, |PC| = 6. Find |PD|. (b) From a point P, 13 from the centre of a circle of radius 5, a tangent touches the circle at T. Find |PT|.
Ask yourself: (a) Product of the parts of one chord equals that of the other. (b) The radius to T is perpendicular to the tangent.
Show the solution
- (a) 4 · 9 = 6 · |PD| ⇒ |PD| = 6.
- (b) Triangle OTP is right-angled at T: |PT| = √13² − 5² = √144 = 12 (a 5-12-13 triple).
Answer (a) 6 (b) 12
Arc, sector and a chord
measurementA circle has radius 6. (a) Find the arc length and sector area for a central angle of 120°. (b) A chord is 8 long; how far is it from the centre?
Ask yourself: (a) 120° is one third of the turn. (b) Drop the perpendicular from the centre: it bisects the chord.
Show the solution
- (a) arc 120360 · 2π · 6 = 4π, sector 120360 · π · 36 = 12π.
- (b) Half-chord 4, radius 6: distance √36 − 16 = √20 = 2√5 ≈ 4.47.
Answer (a) 4π and 12π (b) 2√5
Practice: circle geometry
0 / 0Inscribed and central angles, angles in a semicircle, tangent lengths, crossing chords, arcs and sectors — type 4π or a decimal. Your best score is kept in this browser only.
About this lesson
The circle: central and inscribed angles on the same arc, the angle in a semicircle, the right angle between a radius and a tangent, equal tangents from a point, the intersecting chords and tangent–secant relations, arc length and sector area. Drag the points on the circle, then practise.
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