Graphs of sine, cosine and tangent
Period, amplitude and shift in y = a·sin(bx + c) + d, the tangent’s asymptotes, and radians on the x-axis.
First, the rules
Unroll the unit circle
Walk around the unit circle and plot the height against the angle: that curve is the sine wave. Cosine is the same wave started a quarter turn earlier; tangent runs off to infinity where cosine is zero.
cos x is the same list shifted: 1, 0, −1, 0, 1.
amplitude |a| · period 360° / b · phase shift c (right if positive) · midline y = d · max d + |a|, min d − |a|.
See it
Stretch, squeeze and lift the wave
The dashed curve is the plain function. Change a to stretch it vertically (negative flips it), b to change how many waves fit in 360°, d to lift it. Switch to tangent to see the asymptotes every 180° / b.
Step by step
Worked examples
Sketching one period
key pointsSketch y = cos x for 0° ≤ x ≤ 360° and read off where it is negative.
Ask yourself: Plot the five key points first, then join them with a smooth wave.
Show the solution
- Key points: (0°, 1), (90°, 0), (180°, −1), (270°, 0), (360°, 1).
- The curve starts at its top, dips through 0 at 90°, bottoms out at 180°, returns to 0 at 270° and to the top at 360°.
- It is below the axis strictly between 90° and 270° — exactly the quadrants where cosine is negative on the unit circle.
Answer cos x < 0 for 90° < x < 270°
Reading the equation
amplitude · period · shiftFor y = 3 sin(2x) − 1 give the amplitude, period, maximum, minimum and the first positive x where the maximum is reached.
Ask yourself: Amplitude from a, period from b, the extremes from d ± |a|.
Show the solution
- Amplitude 3; period 360° / 2 = 180°.
- Maximum −1 + 3 = 2, minimum −1 − 3 = −4.
- sin(2x) = 1 first when 2x = 90°, i.e. x = 45°.
Answer 3, 180°, max 2, min −4, first max at 45°
From a graph to an equation
reverseA wave of the form y = a cos(bx) + d (a > 0) has maximum 5, minimum −1 and completes one full wave between x = 0° and x = 120°. Find a, b and d.
Ask yourself: Max and min give a and d; one wave in 120° gives the period, hence b.
Show the solution
- a = (5 − (−1)) / 2 = 3, d = (5 + (−1)) / 2 = 2.
- Period 120° = 360° / b, so b = 3.
- y = 3 cos(3x) + 2. Check: at x = 0 the cosine is 1 and y = 5, the maximum. ✓
Answer y = 3 cos(3x) + 2
Practice: read the equation
0 / 0Amplitude, period, maximum value — or pick the function with a given period. Your best score is kept in this browser only.
About this lesson
Graphs of sine, cosine and tangent: the shape of each curve over a full turn, period, amplitude, vertical shift and phase in y = a·sin(b(x − c)) + d, the asymptotes of tangent, and radians on the axis. Move the sliders, then practise reading period and amplitude from an equation.
Part of Learn mathematics · Grade 11 · Trigonometry. Check a number with the scientific calculator or draw a function with the function plotter. Everything on this page runs in your browser; nothing you type is sent or stored, and your practice score stays in this browser only. Spotted an error? Tell us.